2x^2-20x+32/5x^2-20

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Solution for 2x^2-20x+32/5x^2-20 equation: 


x in (-oo:+oo)

2*x^2+(32/5)*x^2-(20*x)-20 = 0

2*x^2+(32/5)*x^2-20*x-20 = 0

42/5*x^2-20*x-20 = 0

DELTA = (-20)^2-(-20*4*42/5)

DELTA = 1072

DELTA > 0

x = (1072^(1/2)+20)/(2*42/5) or x = (20-1072^(1/2))/(2*42/5)

x = 5/84*(4*67^(1/2)+20) or x = 5/84*(20-4*67^(1/2))

x in { 5/84*(20-4*67^(1/2)), 5/84*(4*67^(1/2)+20) }

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